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What is the rate of reaction when 2 mol of hydrogen gas (H2) react with 1 mol of oxygen gas (O2) to form 2 mol of water (H2O) in 10 minutes at a constant temperature and pressure of 1 atm?

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To calculate the rate of reaction, we need to determine the change in the amount of reactants or products over a given time period. In this case, we are given the initial amounts of reactants and the time it takes for the reaction to occur.The balanced chemical equation for the reaction is:2H g  + O g   2HO g We are given that 2 moles of H and 1 mole of O react to form 2 moles of HO in 10 minutes. To find the rate of reaction, we can use the following formula:Rate of reaction =  Change in amount of reactants or products  /  Time taken for the reaction For H:Rate of reaction =  Initial moles - Final moles  / TimeRate of reaction =  2 moles - 0 moles  / 10 minutesRate of reaction = 2 moles / 10 minutesRate of reaction = 0.2 moles/minuteFor O:Rate of reaction =  Initial moles - Final moles  / TimeRate of reaction =  1 mole - 0 moles  / 10 minutesRate of reaction = 1 mole / 10 minutesRate of reaction = 0.1 moles/minuteSince the rate of reaction for both reactants is proportional to their stoichiometric coefficients in the balanced chemical equation, we can conclude that the rate of reaction for this process is 0.1 moles/minute for O and 0.2 moles/minute for H.

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