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What is the rate of reaction for the combustion of methane in which 4.7 grams of methane reacts in 3.5 seconds to produce 11.2 grams of water vapor and carbon dioxide gas?

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To calculate the rate of reaction for the combustion of methane, we first need to determine the balanced chemical equation for the reaction:CH g  + 2O g   CO g  + 2HO g Now, we need to find the number of moles of methane  CH  that reacted:Moles of CH = mass of CH / molar mass of CHMoles of CH = 4.7 g /  12.01 g/mol  C  + 4 * 1.01 g/mol  H  Moles of CH = 4.7 g / 16.05 g/molMoles of CH  0.2928 molNow, we can calculate the rate of reaction:Rate of reaction = moles of CH / timeRate of reaction = 0.2928 mol / 3.5 sRate of reaction  0.0837 mol/sSo, the rate of reaction for the combustion of methane is approximately 0.0837 mol/s.

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