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What is the polarization in an electrochemical cell when the current density is 200 A/m², the effective surface area of the electrode is 50 cm², the electrode potential is -0.5V and the electrolyte resistance is 10 Ω?

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To calculate the polarization in an electrochemical cell, we need to find the voltage drop across the electrolyte resistance due to the current passing through it. First, we need to convert the effective surface area of the electrode from cm to m:50 cm *  1 m / 10,000 cm  = 0.005 mNext, we can calculate the total current  I  passing through the electrolyte using the current density  J  and the effective surface area  A :I = J * AI = 200 A/m * 0.005 m = 1 ANow, we can calculate the voltage drop  V_drop  across the electrolyte resistance  R  using Ohm's law:V_drop = I * RV_drop = 1 A * 10  = 10 VFinally, we can calculate the polarization  P  by adding the electrode potential  E  and the voltage drop  V_drop :P = E + V_dropP = -0.5 V + 10 V = 9.5 VThe polarization in the electrochemical cell is 9.5 V.

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