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What is the percent yield of silver chloride when 24.5 g of silver nitrate solution reacts with excess sodium chloride to form 23.1 g of silver chloride? The balanced chemical equation is: AgNO3 + NaCl → AgCl + NaNO3.

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To calculate the percent yield, we first need to determine the theoretical yield of silver chloride  AgCl  based on the given mass of silver nitrate  AgNO3 .1. Calculate the moles of AgNO3:Molar mass of AgNO3 = 107.87  Ag  + 14.01  N  + 3 * 16.00  O  = 169.87 g/molmoles of AgNO3 = mass / molar mass = 24.5 g / 169.87 g/mol = 0.144 moles2. From the balanced chemical equation, we know that 1 mole of AgNO3 reacts with 1 mole of NaCl to produce 1 mole of AgCl. Therefore, the moles of AgCl produced are equal to the moles of AgNO3 reacted:moles of AgCl = 0.144 moles3. Calculate the theoretical mass of AgCl:Molar mass of AgCl = 107.87  Ag  + 35.45  Cl  = 143.32 g/moltheoretical mass of AgCl = moles * molar mass = 0.144 moles * 143.32 g/mol = 20.64 g4. Calculate the percent yield:percent yield =  actual yield / theoretical yield  * 100percent yield =  23.1 g / 20.64 g  * 100 = 111.9%However, a percent yield greater than 100% is not possible, as it indicates that more product was formed than theoretically possible. This could be due to experimental error, impurities in the reactants, or an incorrect measurement of the actual yield. Please double-check the given values and ensure they are correct.

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