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What is the magnetic moment of a complex formed between iron(III) ion and ethylenediamine ligand (en) with a coordination number of 6?

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To calculate the magnetic moment of the complex, we need to determine the number of unpaired electrons in the iron III  ion. Iron III  has an oxidation state of +3, so its electronic configuration will be different from that of the neutral iron atom.The electronic configuration of a neutral iron atom  Fe  is [Ar] 3d^6 4s^2. When it forms the Fe III  ion, it loses three electrons, resulting in the electronic configuration [Ar] 3d^5.Now, we can use the formula for calculating the magnetic moment    based on the number of unpaired electrons  n : =  n n+2  In the case of Fe III , there are 5 unpaired electrons  n=5 : =  5 5+2   =  5 7   = 35The magnetic moment of the complex formed between iron III  ion and ethylenediamine ligand  en  with a coordination number of 6 is approximately 35 Bohr magnetons  BM .
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