To calculate the magnetic moment of iron III oxide Fe2O3 at room temperature, we can use the formula:Magnetic moment = n n+2 BM Bohr magneton where n is the number of unpaired electrons and BM is the Bohr magneton 9.274 10^-24 J/T .First, we need to determine the number of unpaired electrons in Fe2O3. Iron III has an oxidation state of +3, meaning it has lost 3 electrons from its 3d and 4s orbitals. The electronic configuration of Fe is [Ar] 3d^6 4s^2, and for Fe III , it is [Ar] 3d^5. There are 5 unpaired electrons in the 3d orbital.Now, we can use the formula to calculate the magnetic moment: = 5 5+2 BM = 5 7 9.274 10^-24 J/T = 35 9.274 10^-24 J/T = 5.92 9.274 10^-24 J/T = 5.48 10^-23 J/THowever, this is the magnetic moment per iron atom. Since there are two iron atoms in the Fe2O3 molecule, we need to multiply the magnetic moment by 2:Magnetic moment of Fe2O3 = 2 5.48 10^-23 J/TMagnetic moment of Fe2O3 = 1.096 10^-22 J/TSo, the calculated magnetic moment of iron III oxide Fe2O3 at room temperature using an experimental molar susceptibility of 5.48 10^-6 cm^3/mol is approximately 1.096 10^-22 J/T.