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What is the lattice energy of sodium chloride (NaCl) given that the distance between the sodium and chloride ions is 2.82 Å and the charges on the ions are +1 and -1 respectively?

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To calculate the lattice energy of sodium chloride  NaCl , we can use the Coulomb's Law formula:Lattice Energy =  k * q1 * q2  / rwhere:k = Coulomb's constant  8.9875517923  10^9 N m^2 C^-2 q1 = charge on the sodium ion  +1 q2 = charge on the chloride ion  -1 r = distance between the ions  2.82  First, we need to convert the distance from angstroms    to meters  m :1  = 1  10^-10 m2.82  = 2.82  10^-10 mNow, we can plug in the values into the formula:Lattice Energy =  8.9875517923  10^9 N m^2 C^-2  *  +1 C  *  -1 C  /  2.82  10^-10 m Lattice Energy = -8.9875517923  10^9 N m^2 C^-2 / 2.82  10^-10 mLattice Energy = -3.189  10^9 N m C^-2The lattice energy of sodium chloride  NaCl  is approximately -3.189  10^9 N m C^-2. Note that the negative sign indicates that the energy is released when the ions come together to form the lattice structure.

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