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What is the calculated lattice energy of NaCl if the distance between the Na+ and Cl- ions in the crystal lattice is 236 pm and the Madelung constant is 1.748?

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To calculate the lattice energy of NaCl, we can use the Born-Lande equation:Lattice Energy  U  =  Madelung constant * charge of cation * charge of anion * electrostatic constant  /  distance between ions where:Madelung constant = 1.748Charge of Na+  cation  = +1  in elementary charge units Charge of Cl-  anion  = -1  in elementary charge units Electrostatic constant  k  = 8.9875  10^9 Nm^2/C^2Distance between ions  r  = 236 pm = 236  10^-12 mNow, we can plug in the values into the equation:U =  1.748 * 1 * -1 * 8.9875  10^9 Nm^2/C^2  /  236  10^-12 m U =  -1.748 * 8.9875  10^9 Nm^2/C^2  /  236  10^-12 m U = -1.571  10^10 Nm^2/C^2 / 2.36  10^-10 mU = -6.66  10^8 J/CSince the charges are in elementary charge units, we need to multiply the result by the elementary charge  e  to get the lattice energy in Joules:Elementary charge  e  = 1.602  10^-19 CLattice Energy  U  = -6.66  10^8 J/C * 1.602  10^-19 CLattice Energy  U  = -1.067  10^-10 JThe calculated lattice energy of NaCl is approximately -1.067  10^-10 Joules.

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