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How much heat is released when 20 grams of methane (CH4) undergoes complete combustion?

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To calculate the heat released during the complete combustion of methane, we need to use the balanced chemical equation for the combustion of methane and the heat of combustion  H  value.The balanced chemical equation for the combustion of methane is:CH4 g  + 2O2 g   CO2 g  + 2H2O l The heat of combustion  H  for methane is -890 kJ/mol.First, we need to convert the mass of methane  20 grams  to moles. The molar mass of methane  CH4  is 12.01 g/mol  C  + 4 * 1.01 g/mol  H  = 16.05 g/mol.Moles of methane = mass / molar mass = 20 g / 16.05 g/mol = 1.246 molesNow, we can calculate the heat released:Heat released = moles of methane * heat of combustionHeat released = 1.246 moles * -890 kJ/mol = -1108.94 kJTherefore, 1108.94 kJ of heat is released during the complete combustion of 20 grams of methane.

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