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What is the heat of sublimation of dry ice (CO2) when 60 grams of it is sublimated at a constant pressure of 1 atm? The initial temperature of dry ice is -78.5°C and its final temperature is -56.6°C.

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To calculate the heat of sublimation of dry ice, we need to know the enthalpy of sublimation for CO2. The enthalpy of sublimation for CO2 is approximately 25.2 kJ/mol.First, we need to convert the mass of dry ice  60 grams  to moles. The molar mass of CO2 is 44.01 g/mol.moles of CO2 = 60 g / 44.01 g/mol = 1.363 molesNow, we can calculate the heat of sublimation for 1.363 moles of CO2:q_sublimation = moles  enthalpy of sublimationq_sublimation = 1.363 moles  25.2 kJ/mol = 34.35 kJTherefore, the heat of sublimation of 60 grams of dry ice at a constant pressure of 1 atm is approximately 34.35 kJ. Note that the initial and final temperatures are not relevant for this calculation, as the heat of sublimation is a constant value for a given substance.

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