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What is the heat of hydration for the dissolution of 10 grams of calcium chloride in 200 mL of water at a temperature of 25 degrees Celsius? Given that the heat of hydration of calcium chloride is -82.8 kJ/mol.

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To calculate the heat of hydration for the dissolution of 10 grams of calcium chloride in 200 mL of water, we need to first determine the number of moles of calcium chloride and then use the heat of hydration value given.Calcium chloride  CaCl  has a molar mass of 40.08 g/mol  Ca  + 2 * 35.45 g/mol  Cl  = 110.98 g/mol.Now, we can find the number of moles of calcium chloride:moles = mass / molar massmoles = 10 g / 110.98 g/mol  0.0901 molNow, we can use the heat of hydration value given  -82.8 kJ/mol  to find the heat of hydration for the dissolution of 10 grams of calcium chloride:q = moles * heat of hydrationq = 0.0901 mol * -82.8 kJ/mol  -7.46 kJThe heat of hydration for the dissolution of 10 grams of calcium chloride in 200 mL of water at a temperature of 25 degrees Celsius is approximately -7.46 kJ.

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