To calculate the heat necessary to increase the temperature of 50 grams of water by 10 degrees Celsius, we need to consider both the heat absorbed by the water and the heat absorbed by the calorimeter.First, let's calculate the heat absorbed by the water. The specific heat capacity of water is 4.18 J/gC. Using the formula q = mcT, where q is the heat, m is the mass, c is the specific heat capacity, and T is the change in temperature:q_water = 50 g 4.18 J/gC 10C = 2090 JNext, let's calculate the heat absorbed by the calorimeter. The heat capacity of the calorimeter is given as 20 J/K which is equivalent to J/C . Using the formula q = CT, where C is the heat capacity:q_calorimeter = 20 J/C 10C = 200 JNow, we add the heat absorbed by the water and the calorimeter to find the total heat necessary:q_total = q_water + q_calorimeter = 2090 J + 200 J = 2290 JSo, the heat necessary to increase the temperature of 50 grams of water by 10 degrees Celsius using a calorimeter with a heat capacity of 20 Joules/Kelvin is 2290 Joules.