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What is the Gibbs free energy change of a spontaneous electrochemical reaction where zinc metal electrode is used as an anode and copper metal electrode is used as a cathode, with a cell potential of 1.10 V?

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To calculate the Gibbs free energy change  G  of a spontaneous electrochemical reaction, we can use the following equation:G = -nFEwhere:- n is the number of moles of electrons transferred in the reaction- F is the Faraday constant  96,485 C/mol - E is the cell potential  1.10 V in this case For the reaction between zinc and copper, the balanced redox reaction is:Zn s  + Cu^2+ aq   Zn^2+ aq  + Cu s In this reaction, 2 moles of electrons are transferred  n = 2  as zinc loses 2 electrons and copper gains 2 electrons.Now we can plug the values into the equation:G = - 2 mol  96,485 C/mol  1.10 V G = -212,667 J/molThe Gibbs free energy change for this spontaneous electrochemical reaction is -212,667 J/mol.

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