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What is the Gibbs free energy change for the reaction of hydrogen gas (H2) and chlorine gas (Cl2) to form hydrochloric acid (2HCl) at standard conditions (298 K and 1 atm)?

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To calculate the Gibbs free energy change  G  for the reaction of hydrogen gas  H2  and chlorine gas  Cl2  to form hydrochloric acid  2HCl  at standard conditions  298 K and 1 atm , we can use the following equation:G = H - TSwhere H is the change in enthalpy, T is the temperature in Kelvin, and S is the change in entropy.First, we need to find the standard enthalpy change  H  and standard entropy change  S  for the reaction. These values can be found in standard thermodynamic tables.For the given reaction:H2 g  + Cl2 g   2HCl g The standard enthalpy change  H  and standard entropy change  S  are as follows:H H2  = 0 kJ/mol  since it is an element in its standard state H Cl2  = 0 kJ/mol  since it is an element in its standard state H HCl  = -92.3 kJ/molS H2  = 130.7 J/molKS Cl2  = 223.1 J/molKS HCl  = 186.8 J/molKNow, we can calculate the changes in enthalpy  H  and entropy  S  for the reaction:H = [2 * H HCl ] - [H H2  + H Cl2 ] = 2 *  -92.3  -  0 + 0  = -184.6 kJ/molS = [2 * S HCl ] - [S H2  + S Cl2 ] = 2 * 186.8 -  130.7 + 223.1  = 373.6 - 353.8 = 19.8 J/molKNow, we can calculate the Gibbs free energy change  G  at 298 K:G = H - TS = -184.6 kJ/mol -  298 K * 19.8 J/molK / 1000 J/kJ  = -184.6 kJ/mol - 5.9 kJ/mol = -190.5 kJ/molSo, the Gibbs free energy change for the reaction of hydrogen gas  H2  and chlorine gas  Cl2  to form hydrochloric acid  2HCl  at standard conditions  298 K and 1 atm  is -190.5 kJ/mol.

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