Question

One mole of neon gas is heated at constant pressure, and its initial temperature is 300 K. The neon gas is then allowed to expand isothermally and reversibly until its volume triples. What is the entropy change of the neon gas during the process?

Answer 1

To calculate the entropy change of the neon gas during the isothermal and reversible expansion, we can use the formula:S = n * R * ln Vf / Vi where S is the entropy change, n is the number of moles, R is the gas constant  8.314 J/molK , Vf is the final volume, and Vi is the initial volume.Since the volume triples, we have:Vf = 3 * ViNow, we can plug in the given values:S =  1 mol  *  8.314 J/molK  * ln 3 * Vi / Vi S = 8.314 J/K * ln 3 S  8.314 J/K * 1.099S  9.13 J/KThe entropy change of the neon gas during the isothermal and reversible expansion is approximately 9.13 J/K.