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What is the entropy change when 2 moles of water vapor (H2O(g)) condense to liquid water (H2O(l)) at 100°C and 1 atm pressure?

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To calculate the entropy change  S  when 2 moles of water vapor condense to liquid water at 100C and 1 atm pressure, we can use the formula:S = n * Hvap / Twhere n is the number of moles, Hvap is the enthalpy of vaporization, and T is the temperature in Kelvin.First, we need to convert the temperature from Celsius to Kelvin:T = 100C + 273.15 = 373.15 KThe enthalpy of vaporization for water is approximately 40.7 kJ/mol. Now, we can calculate the entropy change:S =  2 moles  *  40.7 kJ/mol  /  373.15 K To get the entropy change in J/molK, we need to convert kJ to J:S =  2 moles  *  40,700 J/mol  /  373.15 K S  -218.96 J/molKThe entropy change when 2 moles of water vapor condense to liquid water at 100C and 1 atm pressure is approximately -218.96 J/molK.
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