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What is the enthalpy of combustion of ethane (C2H6), given that the complete combustion of 2.00 grams of ethane in excess oxygen produces 11.2 kJ of heat?

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To calculate the enthalpy of combustion of ethane  C2H6 , we first need to determine the number of moles of ethane combusted and then use the heat produced to find the enthalpy change per mole.First, let's find the molar mass of ethane:C2H6 =  2  12.01 g/mol for C  +  6  1.01 g/mol for H  = 24.02 + 6.06 = 30.08 g/molNow, let's find the number of moles of ethane combusted:moles = mass / molar mass = 2.00 g / 30.08 g/mol = 0.0665 molThe heat produced is given as 11.2 kJ. To find the enthalpy change per mole, we can use the following formula:enthalpy change = heat produced / molesenthalpy change = 11.2 kJ / 0.0665 mol = 168.42 kJ/molSince this is a combustion reaction, the enthalpy change is negative  exothermic reaction . Therefore, the enthalpy of combustion of ethane  C2H6  is approximately -168.42 kJ/mol.

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