To calculate the enthalpy change of hydrolysis for 10 grams of sucrose, we first need to determine the number of moles of sucrose present. The molecular weight of sucrose C12H22O11 is: 12 x 12.01 + 22 x 1.01 + 11 x 16.00 = 144.12 + 22.22 + 176.00 = 342.34 g/molNow, we can find the number of moles of sucrose in 10 grams:moles = mass / molecular weightmoles = 10 g / 342.34 g/mol = 0.0292 molThe enthalpy of hydrolysis for sucrose is given as -564.8 kJ/mol. To find the enthalpy change for the 10 grams of sucrose, we multiply the number of moles by the enthalpy of hydrolysis:H = moles x enthalpy of hydrolysisH = 0.0292 mol x -564.8 kJ/mol = -16.48 kJThe enthalpy change of hydrolysis for 10 grams of sucrose dissolved in 100 mL of water at 25C is approximately -16.48 kJ.