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What is the enthalpy change for the combustion of methane gas (CH4) under standard conditions, given that the enthalpies of formation for CH4 and CO2 are -74.81 kJ/mol and -393.51 kJ/mol respectively?

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To calculate the enthalpy change for the combustion of methane gas  CH4  under standard conditions, we first need to write the balanced chemical equation for the combustion reaction:CH4  g  + 2 O2  g   CO2  g  + 2 H2O  l Next, we need to use the enthalpies of formation for the reactants and products involved in the reaction. The enthalpies of formation for CH4 and CO2 are given as -74.81 kJ/mol and -393.51 kJ/mol, respectively. We also need the enthalpy of formation for H2O  l , which is -285.83 kJ/mol.Now we can use Hess's Law to calculate the enthalpy change for the reaction:H =  [Hf  products ] -  [Hf  reactants ]H = [1   -393.51 kJ/mol  + 2   -285.83 kJ/mol ] - [1   -74.81 kJ/mol  + 2  0 kJ/mol]H =  -393.51 - 571.66 + 74.81  kJ/molH = -890.36 kJ/molThe enthalpy change for the combustion of methane gas  CH4  under standard conditions is -890.36 kJ/mol.

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