Question

What is the enthalpy change associated with the fusion of 45.0 g of ice at 0°C? Given the enthalpy of fusion for water is 6.01 kJ/mol.

Answer 1

To calculate the enthalpy change associated with the fusion of 45.0 g of ice at 0C, we need to first determine the number of moles of ice and then use the enthalpy of fusion for water to calculate the enthalpy change.1. Calculate the number of moles of ice:The molar mass of water  HO  is 18.015 g/mol.Number of moles = mass / molar massn = 45.0 g / 18.015 g/moln  2.50 moles of ice2. Calculate the enthalpy change:Enthalpy change = number of moles  enthalpy of fusionH = 2.50 moles  6.01 kJ/molH  15.03 kJThe enthalpy change associated with the fusion of 45.0 g of ice at 0C is approximately 15.03 kJ.