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What is the enthalpy change (ΔH) for the combustion of methane gas (CH4) at constant pressure (1 atm) if 5.5 grams of methane is completely burned in a bomb calorimeter and the temperature increases by 14.6°C?

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To calculate the enthalpy change  H  for the combustion of methane gas, we need to use the following equation:H = q_p = mcTwhere:q_p = heat absorbed or released at constant pressurem = mass of the substance  in this case, methane c = specific heat capacity of the substanceT = change in temperatureFirst, we need to find the moles of methane  CH4  using its molar mass:Molar mass of CH4 = 12.01 g/mol  C  + 4 * 1.01 g/mol  H  = 16.05 g/molNow, we can find the moles of CH4:moles of CH4 = mass / molar mass = 5.5 g / 16.05 g/mol = 0.3427 molNext, we need to find the heat of combustion of methane  H_combustion . The standard heat of combustion of methane is -890.4 kJ/mol. Since the combustion is exothermic, the heat is released, and the value is negative.Now, we can find the heat released  q_p  during the combustion of 0.3427 mol of CH4:q_p = moles of CH4 * H_combustion = 0.3427 mol * -890.4 kJ/mol = -305.1 kJNow, we can use the equation H = mcT to find the specific heat capacity  c  of methane:c = H /  m * T  = -305.1 kJ /  5.5 g * 14.6C  = -3.8 J/gCFinally, we can calculate the enthalpy change  H  for the combustion of 5.5 grams of methane gas:H = mcT = 5.5 g * -3.8 J/gC * 14.6C = -305.1 kJSo, the enthalpy change  H  for the combustion of 5.5 grams of methane gas at constant pressure  1 atm  is -305.1 kJ.

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