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What is the energy of the vibrational mode that gives rise to an absorption band at 1712 cm$^{-1}$ in the IR spectrum of a molecule of acetic anhydride (C$_4$H$_6$O$_3$)?

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To calculate the energy of the vibrational mode that gives rise to an absorption band at 1712 cm, we can use the formula:E = h * where E is the energy, h is the Planck's constant  6.626 x 10 Js , and  is the frequency of the vibration in Hz.First, we need to convert the wavenumber  1712 cm  to frequency  Hz . We can do this using the speed of light  c  and the following formula: = c * wavenumberThe speed of light  c  is approximately 3.0 x 10 m/s. However, the wavenumber is given in cm, so we need to convert it to m:1712 cm *  1 m / 100 cm  = 17120 mNow, we can calculate the frequency: =  3.0 x 10 m/s  *  17120 m  = 5.136 x 10 HzFinally, we can calculate the energy of the vibrational mode:E =  6.626 x 10 Js  *  5.136 x 10 Hz  = 3.40 x 10 JSo, the energy of the vibrational mode that gives rise to an absorption band at 1712 cm in the IR spectrum of a molecule of acetic anhydride is approximately 3.40 x 10 J.
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