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What is the crystal field stabilization energy (CFSE) for a tetrahedral complex with ligand field splitting parameter (Δt) of 900 cm⁻¹ if it contains three unpaired electrons?

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To calculate the crystal field stabilization energy  CFSE  for a tetrahedral complex, we need to consider the distribution of the unpaired electrons in the d-orbitals. In a tetrahedral complex, the d-orbitals are split into two groups: e  dxy, dxz, dyz  and t2  dx-y, dz .For a tetrahedral complex with three unpaired electrons, the electron configuration will be:e:   3 unpaired electrons t2: emptyNow, we can calculate the CFSE using the ligand field splitting parameter  t  and the number of unpaired electrons in each group:CFSE = -t *  number of electrons in e  +  2/3 t *  number of electrons in t2 In this case, there are 3 electrons in the e orbitals and 0 electrons in the t2 orbitals:CFSE = -900 cm * 3 +  2/3  * 900 cm * 0CFSE = -2700 cmSo, the crystal field stabilization energy  CFSE  for this tetrahedral complex is -2700 cm.

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