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What is the change in enthalpy (ΔH) for the combustion of 10 grams of methane (CH4) at standard conditions, given the following balanced equation: CH4 + 2O2 → CO2 + 2H2O?

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To calculate the change in enthalpy  H  for the combustion of 10 grams of methane  CH4 , we need to know the standard enthalpy of combustion for methane. The standard enthalpy of combustion for methane is -890.4 kJ/mol.First, we need to convert the mass of methane  10 grams  to moles. The molar mass of methane is 12.01 g/mol  C  + 4 * 1.01 g/mol  H  = 16.05 g/mol.Now, we can find the moles of methane:10 g CH4 *  1 mol CH4 / 16.05 g CH4  = 0.623 mol CH4Next, we can calculate the change in enthalpy  H  for the combustion of 0.623 mol of methane:H = moles of CH4 * standard enthalpy of combustionH = 0.623 mol CH4 *  -890.4 kJ/mol H = -555.1 kJTherefore, the change in enthalpy  H  for the combustion of 10 grams of methane  CH4  at standard conditions is -555.1 kJ.

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