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What is the amount of heat energy required to melt 25 grams of ice at 0°C, given that the enthalpy of fusion of water is 6.01 kJ/mol?

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To calculate the amount of heat energy required to melt the ice, we can use the formula:q = n  Hfwhere q is the heat energy, n is the number of moles of the substance, and Hf is the enthalpy of fusion.First, we need to find the number of moles of ice. The molar mass of water  HO  is 18.015 g/mol. n = mass / molar massn = 25 g / 18.015 g/moln  1.387 molesNow, we can calculate the heat energy required to melt the ice:q = n  Hfq = 1.387 moles  6.01 kJ/molq  8.34 kJTherefore, the amount of heat energy required to melt 25 grams of ice at 0C is approximately 8.34 kJ.
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