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What is the amount of heat absorbed in the process of melting 10 grams of ice at 0°C, given that the enthalpy of fusion of ice is 6.01 kJ/mol? Show the calculations and round off to two significant figures.

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To calculate the amount of heat absorbed in the process of melting 10 grams of ice at 0C, we will use the formula:q = n  Hfwhere q is the heat absorbed, n is the number of moles of ice, and Hf is the enthalpy of fusion of ice.First, we need to find the number of moles of ice. The molar mass of water  HO  is approximately 18.015 g/mol. n = mass / molar massn = 10 g / 18.015 g/moln  0.555 molNow, we can calculate the heat absorbed:q = n  Hfq = 0.555 mol  6.01 kJ/molq  3.34 kJThe amount of heat absorbed in the process of melting 10 grams of ice at 0C is approximately 3.34 kJ, rounded off to two significant figures.
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