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What is the amount of heat absorbed by a 50 g sample of water when it is heated from 20°C to 100°C? (Specific heat of water= 4.18 J/g·K)

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To calculate the amount of heat absorbed by the water, we can use the formula:q = mcTwhere q is the heat absorbed, m is the mass of the water, c is the specific heat of water, and T is the change in temperature.Given:m = 50 gc = 4.18 J/gKInitial temperature  T1  = 20CFinal temperature  T2  = 100CFirst, we need to find the change in temperature  T :T = T2 - T1T = 100C - 20CT = 80CNow, we can plug the values into the formula:q =  50 g    4.18 J/gK    80 K q = 50  4.18  80q = 16720 JSo, the amount of heat absorbed by the 50 g sample of water when heated from 20C to 100C is 16,720 Joules.

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