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What is the activation energy for a chemical reaction that has a rate constant of 2.5 × 10^-3 s^-1 at a temperature of 298 K, when the frequency factor is 5 × 10^13 s^-1?

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To calculate the activation energy  Ea  for the chemical reaction, we can use the Arrhenius equation:k = A * e^-Ea / RT where k is the rate constant  2.5  10^-3 s^-1 , A is the frequency factor  5  10^13 s^-1 , R is the gas constant  8.314 J/mol K , and T is the temperature  298 K .First, we need to isolate Ea in the equation:k / A = e^-Ea / RT Now, take the natural logarithm of both sides:ln k / A  = -Ea / RTNext, multiply both sides by -RT:Ea = -RT * ln k / A Now, plug in the values:Ea = -  8.314 J/mol K  *  298 K  * ln  2.5  10^-3 s^-1  /  5  10^13 s^-1  Ea  96452.5 J/molThe activation energy for the chemical reaction is approximately 96,452.5 J/mol.

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