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What is the exact stoichiometric ratio of benzyl chloride and ammonia required for the preparation of 1 mole of phenylalanine, assuming complete conversion and a yield of 100%?

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The synthesis of phenylalanine from benzyl chloride and ammonia can be represented by the following balanced chemical equation:C6H5CH2Cl + 2 NH3  C6H5CH2NH2 + NH4ClIn this reaction, 1 mole of benzyl chloride  C6H5CH2Cl  reacts with 2 moles of ammonia  NH3  to produce 1 mole of phenylalanine  C6H5CH2NH2  and 1 mole of ammonium chloride  NH4Cl .Therefore, the exact stoichiometric ratio of benzyl chloride to ammonia required for the preparation of 1 mole of phenylalanine is 1:2, assuming complete conversion and a yield of 100%.
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