0 votes
34 views
in Chemical synthesis by (138k points)
What is the optimal molar ratio of toluene to nitric acid needed to produce the maximum yield of 2,4,6-trinitrotoluene in the chemical synthesis process?

1 Answer

0 votes
by (138k points)
The synthesis of 2,4,6-trinitrotoluene  TNT  involves two main steps: nitration of toluene to form dinitrotoluene  DNT  and further nitration of DNT to form TNT. In both steps, a mixture of nitric acid and sulfuric acid is used as the nitrating agent.1. Nitration of toluene to form dinitrotoluene  DNT :C6H5CH3 + 2HNO3 -> C6H3 CH3  NO2 2 + 2H2O2. Nitration of dinitrotoluene to form 2,4,6-trinitrotoluene  TNT :C6H3 CH3  NO2 2 + HNO3 -> C6H2 CH3  NO2 3 + H2OFrom the balanced equations, we can see that the overall stoichiometry for the synthesis of TNT is:C6H5CH3 + 3HNO3 -> C6H2 CH3  NO2 3 + 3H2OThus, the optimal molar ratio of toluene to nitric acid for the maximum yield of TNT is 1:3.
Welcome to Sarvan Science Q&A, where you can ask questions and receive answers from other members of the community.
...