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What is the standard enthalpy change of neutralization for the reaction between hydrochloric acid and sodium hydroxide? Show all calculations and provide a conclusion based on your result.

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The standard enthalpy change of neutralization  H_neutralization  is the enthalpy change when one mole of water is formed from the reaction between an acid and a base under standard conditions  298 K and 1 atm pressure . In this case, we are looking at the reaction between hydrochloric acid  HCl  and sodium hydroxide  NaOH .The balanced chemical equation for this reaction is:HCl aq  + NaOH aq   NaCl aq  + H2O l The standard enthalpy change of neutralization for the reaction between a strong acid and a strong base, such as HCl and NaOH, is approximately -57.1 kJ/mol. This value is obtained from experimental data and is considered a constant for strong acid-strong base reactions.In this case, since both HCl and NaOH are strong acids and bases, the standard enthalpy change of neutralization for their reaction is:H_neutralization = -57.1 kJ/molConclusion: The standard enthalpy change of neutralization for the reaction between hydrochloric acid and sodium hydroxide is -57.1 kJ/mol. This means that the reaction is exothermic, releasing energy in the form of heat when one mole of water is formed from the reaction between HCl and NaOH under standard conditions.

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