The redox reaction between hydrogen peroxide H2O2 and potassium permanganate KMnO4 can be represented by the following balanced chemical equation:2 KMnO4 + 5 H2O2 + 6 H+ 2 Mn2+ + 8 H2O + 5 O2The corresponding redox half-reactions are:Oxidation half-reaction H2O2 :H2O2 O2 + 2 H+ + 2 e-Reduction half-reaction KMnO4 :MnO4- + 8 H+ + 5 e- Mn2+ + 4 H2OWhen the pH of the reaction is increased, the concentration of H+ ions decreases. This affects the reduction half-reaction, as the reduction of MnO4- to Mn2+ requires H+ ions. As the concentration of H+ ions decreases, the reduction half-reaction will be less favored, and the equilibrium position will shift to the left.This means that at higher pH values, the reaction between hydrogen peroxide and potassium permanganate will be less efficient, and the equilibrium position will favor the reactants H2O2 and KMnO4 over the products Mn2+, H2O, and O2 .