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What is the mechanism behind the reaction of propyne with hydrogen chloride, and what is the product formed?

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The reaction of propyne  CHCCH  with hydrogen chloride  HCl  is an electrophilic addition reaction. The mechanism involves the following steps:1. Protonation of the alkyne: The hydrogen atom from HCl acts as an electrophile and attacks the electron-rich triple bond of propyne. The pi electrons from the triple bond form a bond with the hydrogen atom, creating a carbocation intermediate and leaving a chloride ion  Cl  in the solution. The carbocation intermediate has a double bond  C=C  and a positive charge on the carbon atom adjacent to the CH group.2. Nucleophilic attack by chloride ion: The chloride ion  Cl , which is a nucleophile, attacks the positively charged carbon atom in the carbocation intermediate, forming a bond with it. This results in the formation of the final product.The product formed in this reaction is 1-chloro-2-propene  CHC Cl =CH , also known as 1-chloropropene. This product is a haloalkene, which is formed by the addition of HCl across the triple bond of propyne.
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