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What is the mechanism of the reaction for the preparation of 4-bromoacetanilide from acetanilide and bromine? Provide a detailed step-by-step process with energy changes and intermediate formation.

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The preparation of 4-bromoacetanilide from acetanilide and bromine involves an electrophilic aromatic substitution reaction. Here is a detailed step-by-step process with energy changes and intermediate formation:1. Generation of electrophile:Bromine  Br2  reacts with a Lewis acid catalyst, such as aluminum bromide  AlBr3  or iron III  bromide  FeBr3 , to form a highly electrophilic bromonium ion  Br+ . This step is endothermic as energy is required to break the Br-Br bond and form the electrophile.Br2 + AlBr3  Br+ + AlBr4-2. Formation of sigma complex  arenium ion :The electrophilic bromonium ion  Br+  attacks the aromatic ring of acetanilide at the para position  due to the activating effect of the amino group  to form a sigma complex, also known as an arenium ion. This step is also endothermic as energy is required to break the aromaticity of the ring and form a new bond between the carbon and the electrophile.Acetanilide + Br+  para-Arenium ion  sigma complex 3. Rearrangement and deprotonation:A proton from the carbon adjacent to the newly attached bromine atom is removed by the AlBr4- ion  or another base , which acts as a base. This step is exothermic as energy is released when the aromaticity of the ring is restored and a new C-Br bond is formed.para-Arenium ion  sigma complex  + AlBr4-  4-bromoacetanilide + HAlBr4Overall, the reaction is an electrophilic aromatic substitution, and the energy changes involve endothermic steps for electrophile generation and sigma complex formation, followed by an exothermic step for deprotonation and product formation. The intermediate formed during the reaction is the para-arenium ion  sigma complex .
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