The nucleophilic substitution reaction of 2-bromopentane with sodium methoxide follows an SN2 substitution nucleophilic bimolecular mechanism. Here's the complete reaction pathway:1. Sodium methoxide NaOCH3 dissociates into sodium Na+ and methoxide CH3O- ions. Methoxide is a strong nucleophile.2. The methoxide ion CH3O- attacks the electrophilic carbon atom C2 of 2-bromopentane from the backside, opposite to the bromine atom. This backside attack leads to the inversion of configuration at the carbon center.3. As the methoxide ion forms a bond with the electrophilic carbon, the carbon-bromine bond starts to break, and the bromine atom leaves as a bromide ion Br- .4. The product is 2-methoxypentane, and the leaving group is the bromide ion Br- . The sodium ion Na+ associates with the bromide ion to form sodium bromide NaBr .Overall reaction: 2-bromopentane + sodium methoxide -> 2-methoxypentane + sodium bromideThere are no intermediates in this reaction, as the SN2 mechanism involves a single concerted step. The products are 2-methoxypentane and sodium bromide.