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What is the mechanism of nucleophilic substitution reaction for the conversion of 2-bromobutane to 2-butanol using sodium hydroxide as a nucleophile?

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The mechanism of the nucleophilic substitution reaction for the conversion of 2-bromobutane to 2-butanol using sodium hydroxide  NaOH  as a nucleophile is an SN2  Substitution Nucleophilic Bimolecular  reaction. Here's a step-by-step description of the mechanism:1. Formation of nucleophile: Sodium hydroxide  NaOH  dissociates into sodium cation  Na+  and hydroxide anion  OH- . The hydroxide anion acts as a nucleophile in this reaction.NaOH  Na+ + OH-2. Nucleophilic attack: The hydroxide anion  OH-  attacks the electrophilic carbon atom  C2  of 2-bromobutane from the backside, opposite to the leaving group  Br- . This backside attack leads to the inversion of the stereochemistry at the carbon center.OH- + CH3CHBrCH2CH3  [CH3CHOHCH2CH3Br]-3. Departure of the leaving group: The bromide ion  Br-  leaves the transition state, and the bond between the carbon atom  C2  and the bromine atom is broken.[CH3CHOHCH2CH3Br]-  CH3CHOHCH2CH3 + Br-4. Formation of the product: The final product, 2-butanol, is formed along with the bromide ion.Overall reaction: CH3CHBrCH2CH3 + NaOH  CH3CHOHCH2CH3 + NaBrIn summary, the mechanism of the nucleophilic substitution reaction for the conversion of 2-bromobutane to 2-butanol using sodium hydroxide as a nucleophile is an SN2 reaction involving the attack of the hydroxide anion on the electrophilic carbon, the departure of the bromide ion as a leaving group, and the formation of 2-butanol as the product.
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