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Identify the type of inorganic solid formed between sodium and chlorine, and explain the bonding present in the solid.

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The inorganic solid formed between sodium and chlorine is sodium chloride  NaCl , which is commonly known as table salt. The bonding present in this solid is ionic bonding.Ionic bonding occurs when there is a transfer of electrons between a metal and a non-metal atom. In the case of sodium chloride, sodium  Na  is a metal, and chlorine  Cl  is a non-metal. Sodium has one electron in its outermost shell, while chlorine has seven electrons in its outermost shell. To achieve a stable electron configuration, sodium loses its one valence electron, and chlorine gains one electron to complete its outermost shell.As a result of this electron transfer, sodium becomes a positively charged ion  Na+ , and chlorine becomes a negatively charged ion  Cl- . The electrostatic attraction between these oppositely charged ions forms the ionic bond, which holds the sodium and chlorine ions together in a crystal lattice structure. This type of bonding results in a highly stable and well-organized solid with high melting and boiling points, as well as good solubility in water.
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