The heat of hydration for magnesium sulfate MgSO4 is the amount of heat released when one mole of the substance is dissolved in water. To calculate the heat of hydration for 10 grams of magnesium sulfate, we need to know the molar heat of hydration for MgSO4 and the molar mass of MgSO4.The molar heat of hydration for magnesium sulfate heptahydrate MgSO47H2O is -104.86 kJ/mol.The molar mass of MgSO47H2O is:Mg = 24.31 g/molS = 32.07 g/molO4 = 4 * 16.00 g/mol = 64.00 g/mol7H2O = 7 * 2 * 1.01 g/mol + 16.00 g/mol = 7 * 18.02 g/mol = 126.14 g/molMolar mass of MgSO47H2O = 24.31 + 32.07 + 64.00 + 126.14 = 246.52 g/molNow, we can find the moles of MgSO47H2O in 10 grams:moles = mass / molar mass = 10 g / 246.52 g/mol = 0.0406 molFinally, we can calculate the heat of hydration for 10 grams of MgSO47H2O:q = moles * molar heat of hydration = 0.0406 mol * -104.86 kJ/mol = -4.26 kJSo, the heat of hydration for 10 grams of magnesium sulfate when dissolved in 100 mL of water is approximately -4.26 kJ.