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ago in ThermoChemistry by (2.2k points)
What is the heat capacity of a substance if it takes 345 Joules of energy to raise the temperature of 15 grams of the substance by 12 degrees Celsius?

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The heat capacity  C  of a substance can be calculated using the formula:q = mcTwhere q is the heat energy  in Joules , m is the mass of the substance  in grams , c is the specific heat capacity  in J/gC , and T is the change in temperature  in C .We are given the following values:q = 345 Jm = 15 gT = 12 CWe need to find the specific heat capacity  c  of the substance. Rearranging the formula to solve for c, we get:c = q /  mT Now, plug in the given values:c = 345 J /  15 g  12 C c = 345 J / 180 gCc = 1.92 J/gCThe heat capacity of the substance is 1.92 J/gC.
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