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What is the exchange current density for the oxidation reaction of copper in a 1 M CuSO4 solution, given that the electrochemical rate constant is 5.2 × 10^-3 cm/s and the surface area of the electrode is 0.05 cm^2?

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The exchange current density  i0  is a measure of the rate of an electrochemical reaction and can be calculated using the following formula:i0 = k0 * n * F * C * Awhere:- i0 is the exchange current density  A/cm - k0 is the electrochemical rate constant  cm/s - n is the number of electrons transferred in the reaction  for the oxidation of copper, Cu -> Cu + 2e, n = 2 - F is the Faraday constant  96485 C/mol - C is the concentration of the reactant  1 M for CuSO solution - A is the surface area of the electrode  0.05 cm Now, we can plug in the values and calculate the exchange current density:i0 =  5.2  10^-3 cm/s  * 2 *  96485 C/mol  *  1 mol/L  *  0.05 cm i0 = 0.0104 * 96485 * 0.05i0 = 50.3444 A/cmThe exchange current density for the oxidation reaction of copper in a 1 M CuSO solution is approximately 50.34 A/cm.

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