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What is the efficiency of an electrochemical cell when the electrode potential is +0.6V and the cell voltage is 1.8V?

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The efficiency of an electrochemical cell can be calculated using the following formula:Efficiency =  Actual cell voltage / Maximum possible cell voltage   100%In this case, the actual cell voltage is given as 1.8V, and the electrode potential is +0.6V. Since there are two electrodes in an electrochemical cell, the maximum possible cell voltage would be the sum of the potentials of both electrodes.Maximum possible cell voltage = 2  0.6V = 1.2VNow, we can calculate the efficiency:Efficiency =  1.8V / 1.2V   100% = 1.5  100% = 150%However, this result indicates that the efficiency is greater than 100%, which is not possible for any real system. There might be an error in the given data or a misunderstanding of the problem. Please recheck the values and the context of the problem.

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