The effect on the solubility of AgCl in water when the concentration of NaCl is increased is that the solubility of AgCl will decrease. This is due to the common ion effect, where the presence of a common ion in this case, Cl- will suppress the solubility of the sparingly soluble salt AgCl .To calculate the new solubility of AgCl when the concentration of NaCl is increased from 0.1 M to 0.3 M, we can use the solubility product constant Ksp expression:Ksp = [Ag+][Cl-]Given that the Ksp of AgCl is 1.77 x 10^-10, we can set up the following equation:1.77 x 10^-10 = [Ag+][0.3]Now, we need to solve for the concentration of Ag+ ions:[Ag+] = 1.77 x 10^-10 / 0.3[Ag+] 5.9 x 10^-10 MSo, the new solubility of AgCl when the concentration of NaCl is increased from 0.1 M to 0.3 M is approximately 5.9 x 10^-10 M.