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What is the rate constant for the decomposition of N<sub>2</sub>O<sub>5</sub> at 298 K if the half-life is 15.6 minutes and the initial concentration is 0.1 M?

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The decomposition of N2O5 is a first-order reaction, which means that the rate of the reaction depends on the concentration of N2O5. The rate law for a first-order reaction is:rate = k[N2O5]where k is the rate constant and [N2O5] is the concentration of N2O5.The half-life  t1/2  of a first-order reaction is related to the rate constant by the following equation:t1/2 = 0.693 / kGiven the half-life  t1/2  of 15.6 minutes, we can solve for the rate constant  k :15.6 minutes = 0.693 / kRearranging the equation to solve for k:k = 0.693 / 15.6 minutesk  0.0445 min^-1 So, the rate constant for the decomposition of N2O5 at 298 K is approximately 0.0445 min^-1 .

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