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What is the complete combustion equation for ethane (C2H6) and how many moles of oxygen gas (O2) are required for the reaction to produce 5 moles of carbon dioxide gas (CO2) and 6 moles of water vapor (H2O)?

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The complete combustion equation for ethane  C2H6  is:C2H6 + 7/2 O2  2 CO2 + 3 H2ONow, let's find out how many moles of oxygen gas  O2  are required for the reaction to produce 5 moles of carbon dioxide gas  CO2  and 6 moles of water vapor  H2O .From the balanced equation, we can see that 2 moles of CO2 are produced for every 7/2 moles of O2 consumed. To find the moles of O2 required to produce 5 moles of CO2, we can set up a proportion: 7/2 moles O2  /  2 moles CO2  = x moles O2 /  5 moles CO2 Solving for x:x moles O2 =  7/2 moles O2  *  5 moles CO2  /  2 moles CO2 x moles O2 = 35/4 moles O2Therefore, 35/4 moles of oxygen gas  O2  are required for the reaction to produce 5 moles of carbon dioxide gas  CO2  and 6 moles of water vapor  H2O .

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