The complete combustion equation for ethane C2H6 is:C2H6 + 7/2 O2 2 CO2 + 3 H2ONow, let's find out how many moles of oxygen gas O2 are required for the reaction to produce 5 moles of carbon dioxide gas CO2 and 6 moles of water vapor H2O .From the balanced equation, we can see that 2 moles of CO2 are produced for every 7/2 moles of O2 consumed. To find the moles of O2 required to produce 5 moles of CO2, we can set up a proportion: 7/2 moles O2 / 2 moles CO2 = x moles O2 / 5 moles CO2 Solving for x:x moles O2 = 7/2 moles O2 * 5 moles CO2 / 2 moles CO2 x moles O2 = 35/4 moles O2Therefore, 35/4 moles of oxygen gas O2 are required for the reaction to produce 5 moles of carbon dioxide gas CO2 and 6 moles of water vapor H2O .