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What is the boiling point of sodium chloride (NaCl) at a pressure of 1 atm? Show the calculation using the Clausius-Clapeyron equation.

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ago by (250 points)
The Clausius-Clapeyron equation is used to determine the vapor pressure of a substance at different temperatures. However, sodium chloride  NaCl  is a solid at room temperature and does not have a boiling point at 1 atm pressure. Instead, it has a melting point at 1 atm, which is around 801C  1074 K .If you are looking for the boiling point of a solution containing NaCl, such as a saltwater solution, the boiling point elevation can be calculated using the equation:Tb = Kb * molality * iwhere Tb is the boiling point elevation, Kb is the ebullioscopic constant for water  0.512Ckg/mol , molality is the molality of the solution  moles of solute per kilogram of solvent , and i is the van't Hoff factor  number of ions produced per formula unit of solute, which is 2 for NaCl .However, this equation is not applicable for pure NaCl. In the case of pure NaCl, it will undergo sublimation  directly convert from solid to gas  at very high temperatures and low pressures. The sublimation temperature of NaCl is around 1465C  1738 K  at a pressure of 1 atm.
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