0 votes
17 views
ago in Chemical bonding by (330 points)
What is the bond enthalpy of O-H bond in the molecule H2O? Show the calculation involved in determining the enthalpy change required to break one mole of O-H bonds in water.

1 Answer

0 votes
ago by (170 points)
The bond enthalpy of the O-H bond in water  H2O  is the amount of energy required to break one mole of O-H bonds in the molecule. The bond enthalpy of the O-H bond in water is approximately 463 kJ/mol.To calculate the enthalpy change required to break one mole of O-H bonds in water, we need to consider that there are two O-H bonds in one molecule of water. Therefore, the enthalpy change for breaking one mole of O-H bonds in water can be calculated as follows:Enthalpy change = Bond enthalpy of O-H bond  Number of O-H bonds in one molecule of waterEnthalpy change = 463 kJ/mol  2Enthalpy change = 926 kJ/molSo, the enthalpy change required to break one mole of O-H bonds in water is 926 kJ/mol.

Related questions

Welcome to Sarvan Science Q&A, where you can ask questions and receive answers from other members of the community.
...