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What is the balanced redox reaction for the combustion of methane (CH4) in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O)?
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Chemical reactions
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SherrylR3277
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What is the balanced redox reaction for the combustion of methane (CH4) in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O)?
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MerleThornbe
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The balanced redox reaction for the combustion of methane CH4 in the presence of oxygen O2 to form carbon dioxide CO2 and water H2O is as follows:CH4 + 2 O2 CO2 + 2 H2O
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Sure. Here's a precise problem for a chemistry student to solve: What is the balanced chemical equation for the combustion of methane gas (CH4) in the presence of oxygen gas (O2) to produce carbon dioxide gas (CO2) and water vapor (H2O)?
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What is the balanced chemical equation for the combustion of methane (CH4) in the presence of oxygen (O2)? What is the theoretical yield of carbon dioxide (CO2) if 10 moles of methane are combusted completely?
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Here's a precise problem for a chemistry student to solve:Using Hess's Law, calculate the enthalpy change for the reaction where 2 moles of methane (CH4) reacts with 4 moles of oxygen gas (O2) to form 2 moles of carbon dioxide (CO2) and 4 moles of water (H2O), given the following known enthalpy changes:ΔH1 = -890 kJ/mol for the reaction: CH4 + 2O2 → CO2 + 2H2OΔH2 = -394 kJ/mol for the reaction: C + O2 → CO2ΔH3 = -286 kJ/mol for the reaction: H2 + (1/2)O2 → H2O
asked
Feb 4
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Chemical reactions
by
ClaraNdw6090
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Calculate the enthalpy change for the combustion of methane gas (CH4) at standard conditions given the following information: 4 moles of methane gas is burned in excess oxygen gas (O2) to form carbon dioxide gas (CO2) and liquid water (H2O). The enthalpy change for the combustion of 1 mole of methane gas is -890.4 kJ/mol.
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