Question

What is the equilibrium constant for the reaction between nitrogen gas and hydrogen gas to form ammonia gas at 500°C given that the equilibrium concentrations are [N2] = 0.25 M, [H2] = 0.20 M and [NH3] = 0.10 M?

Answer 1

The balanced chemical equation for the formation of ammonia from nitrogen and hydrogen gases is:N2 g  + 3H2 g   2NH3 g To find the equilibrium constant  Kc  for this reaction, we can use the equilibrium concentrations given:[N2] = 0.25 M[H2] = 0.20 M[NH3] = 0.10 MThe expression for Kc is:Kc = [NH3]^2 /  [N2] * [H2]^3 Now, we can plug in the equilibrium concentrations:Kc =  0.10 ^2 /  0.25 *  0.20 ^3 Kc = 0.01 /  0.25 * 0.008 Kc = 0.01 / 0.002Kc = 5So, the equilibrium constant for the reaction between nitrogen gas and hydrogen gas to form ammonia gas at 500C is 5.