The balanced chemical equation for the decomposition of potassium chlorate KClO3 when heated is:2 KClO3 s 2 KCl s + 3 O2 g To calculate the amount of oxygen produced from the decomposition of 50 grams of potassium chlorate, we will use stoichiometry.First, we need to find the molar mass of KClO3:K = 39.10 g/molCl = 35.45 g/molO = 16.00 g/molMolar mass of KClO3 = 39.10 + 35.45 + 3 16.00 = 122.55 g/molNow, we can convert the mass of KClO3 to moles:50 g KClO3 1 mol KClO3 / 122.55 g KClO3 = 0.408 moles KClO3Using the stoichiometry from the balanced equation, we can find the moles of O2 produced:0.408 moles KClO3 3 moles O2 / 2 moles KClO3 = 0.612 moles O2Finally, we can convert the moles of O2 to grams:0.612 moles O2 32.00 g/mol O2 = 19.58 grams O2So, the amount of oxygen produced from the decomposition of 50 grams of potassium chlorate is approximately 19.58 grams.