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How does the addition of a catalyst affect the equilibrium position of a chemical reaction and how can it be calculated mathematically? Use the reaction A + B ⇌ C + D as an example and show step-by-step calculations for the effect of adding a catalyst.

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The addition of a catalyst to a chemical reaction does not affect the equilibrium position of the reaction. A catalyst works by lowering the activation energy of the reaction, which increases the rate at which the reaction proceeds in both the forward and reverse directions. However, the equilibrium constant  K  remains unchanged, as it is only affected by temperature.To demonstrate this, let's consider the reaction:A + B  C + DThe equilibrium constant  K  for this reaction can be expressed as:K = [C][D] / [A][B]where [A], [B], [C], and [D] represent the concentrations of the respective species at equilibrium.Now, let's assume we add a catalyst to the reaction. The catalyst will increase the rate of the forward reaction  k1  and the reverse reaction  k2  by the same factor. This means that the ratio of the rate constants remains the same:k1 / k2 = k1' / k2'where k1 and k2 are the rate constants without the catalyst, and k1' and k2' are the rate constants with the catalyst.Since the equilibrium constant  K  is defined as the ratio of the rate constants:K = k1 / k2and because the ratio of the rate constants remains the same with the addition of the catalyst:K = k1' / k2'Thus, the equilibrium constant  K  and the equilibrium position remain unchanged when a catalyst is added to the reaction. The only effect of the catalyst is to increase the rate at which the reaction reaches equilibrium, but it does not change the equilibrium concentrations of the reactants and products.

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